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Category:Indian classical music
Category:Sanskrit words and phrasesDose reduction in radiation therapy using computer-simulated tomography.
A fully 3-dimensional procedure is described which allows the dose distribution in a phantom to be computed with the aid of the results of a computer-simulated tomography scan. The technique permits the physician to compare a calculated dose distribution with a measured one and estimate the dose that will be received by a patient during a radiation treatment. An overview of the method and the preliminary results obtained in a simulation of a head irradiation are presented.Q:
What would be a more intuitive method for applying a function to a matrix than nested for loops?
I'm trying to create a function that will take a vector and a matrix and apply the specified function to each element of the vector and then return a new matrix.
So far I have this:
function lm(.vector,.matrix)
for i = 1 : n
for j = 1 : m
x(i) = x(i) * matrix(j,:)
end
x(i) =.vector
end
return x
This works and is fine, but is there a more intuitive way to do this? It seems like it could be possible but I can't seem to find a working solution.
A:
The @() is for indexing vector and matrix by a subscript index (another alternative is to use. operator). So, you can simply index x by the two for-loops indices (i and j):
x =.vector * matrix(:,j)
If x's size(x) is not equal to n and m, you can wrap it in a cell array:
x = cell(n, m);
for i = 1:n
for j = 1:m
x{i,j} =.vector * matrix(:,j)
end
end
And if x is of class, for example, cell, you can use the element:
x =.vector * matrix(:,j);
x = cell2mat(x);
As @matt mentioned, x(:) is just a way to define a matrix of x.
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